Q.

A particle moving along X-axis has acceleration ‘f’ at time ‘t’ given by f=f01-tT where f0, T are constants. The particle at t = 0 has zero velocity. In the time interval between t = 0 and the instant when f = 0, the particle velocity v0 is

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a

12f0T2

b

f0T2

c

12f0T

d

f0T

answer is C.

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Detailed Solution

at t=0 , v=0 acceleration f = f01-1T

At f=0; t=T

f=dvdt

0vxdv=t=0t=Tfdt Solving we  get 12f0T

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