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Q.

A particle moving along x-axis has acceleration f, at time t, given by f=f01tT, where f0 and T are constants. The particle at t = 0 has zero velocity. In the time interval between t = 0 and the instant when f=0, the particle’s velocity (vx) is

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a

12f0T2

b

f0T

c

12f0T

d

f0T2

answer is C.

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Detailed Solution

f=f01tTdvdt=f01tTdv=f01tTdtV=dv=f01tTdtv=f0tt22T+c; At t=0;v=0;c=0v=f0tt22T

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