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Q.

A particle moving along X-axis has acceleration 'f ' at time t, given by f=fo1-tT where fo and T are constants. The particle at t = 0 has zero velocity. In the time interval between t = 0 and the instant when f = 0, the particle's velocity (vx) is:

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a

12foT2

b

foT2

c

12foT

d

foT

answer is C.

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Detailed Solution

Acceleration, dvxdt=f=f01tT
ovxdvx=fott2T0T
vx=fott22ToT
=foTT22T
=12foT 

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