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A particle moving along x-axis has, at any instant, its x - coordinate to be x = 4 + 3t + 5t² . What is the value of $\frac{dx}{dt}$ at t = 1?

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Detailed Solution

X = 4 + 3t + 5t²
$\Rightarrow \frac{dx}{dt} = 0 + 3 (1) + 5 (2 t) = 3 + 10 t$
$At t = 1, \frac{dx}{dt} = 3 + 10 (1) = 13$

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