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Q.

A particle moving in a straight line covers half the distance with speed of 3 ms-1. The other half of the distance is covered in two equal time intervals with a speeds of 4.5 ms-1 and 7.5 ms-1 respectively. Find the average speed (in m/s) of the particle during this motion

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Detailed Solution

vavg=2v0v1+v22v0+v1+v2⇒vavg=2×3(4.5+7.5)6+4.5+7.5ms−1⇒vavg=6×1218ms−1=4ms−1

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