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Q.

A particle moving rectilinearly with constant acceleration is having initial velocity of 10 m/s. After some time, its velocity becomes 30 m/s. Find out velocity of the particle at the mid point of its path?

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a

$20 m$

b

$10 \sqrt{2} m$

c

$25 m$

d

$10 \sqrt{5} m$

answer is D.

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Detailed Solution

From equations of motion
$v^{2} - 10^{2} = 2 a s - - - - (i)$

$30^{2} - v^{2} = 2 a s - - - - - (i i)$
Solving we get,v= $10 \sqrt{5}$

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