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Q.

A particle moving with a constant acceleration describes in the last second of its motion 9/ 25th of the whole distance. If it starts from rest, how long is the particle in motion and through what distance does it move if it describes 6 cm in the first sec.?

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a

15 s ; 100 cm

b

5 s; 150 cm

c

None

d

10 s ; 150 cm

answer is A.

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Detailed Solution

u = 0
sns=2n−1n2=925
⇒n=   5
u = 0 ⇒s∝t2
s1s2=t1t226s2=152
s2 = 6 × 25 = 150cm

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