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Q.

A particle moving with a uniform acceleration travels 24 m and 64 m in the first two consecutive intervals of 4 sec each. Its initial velocity is

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a

5 m/sec

b

2 m/sec

c

10 m/sec

d

1 m/sec

answer is A.

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Detailed Solution

Distance travelled in 4 sec
24=4u+12a×16.....(i)
Distance travelled in total 8 sec
88=8u+12a×64...(ii)
After solving (i) and (ii), we get u = 1 m/s.

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