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A particle moving with a velocity equal to 0.4 m/s is subjected to an acceleration of 0.15 $m s^{- 2}$ for 2 sec in a direction at right angles to its direction of motion. The resultant velocity is:

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0.7 m/s

0.5 m/s

0. 1 m/s

between 0.7 and 0.1 m/s

answer is B.

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Detailed Solution

Resultant velocity = $\sqrt{{(0.4)}^{2} + {(0.15 \times 2)}^{2}} = 0.5 m / s$

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