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Q.

A particle moving with constant acceleration, travels 10 m in the first 5 second and another 10 m in the next 3 second. The distance, it will travel in the next 2 second will be:

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a

8.33 m

b

5.67 m

c

9.37 m

d

10 m

answer is A.

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Detailed Solution

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By using $s = ut + \frac{1}{2} {at}^{2}; 10 = u (5) + \frac{1}{2} a {(5)}^{2}$ and
$10 + 10 = u (5 + 3) + \frac{1}{2} a {(5 + 3)}^{2} \Rightarrow u = \frac{7}{6} m / s$ and $a = \frac{1}{3} m / s^{2}$
Distance travelled in next 2s $u (10) + \frac{1}{2} a {(10)}^{2} - 20 = 8 .33 m$

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