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Q.

A particle moving with kinetic energy E has de Broglie wavelength  λ. If energy  ΔE is added to its energy, the wavelength become λ/2 . Value of  ΔE is:

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a

3E

b

2E

c

4E

d

E

answer is C.

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Detailed Solution

de Broglie wavelength=λ=h2E m       ​ ⇒ λ ∝  1E ⇒E∝1λ2​If λ becomes half, then E becomes 4 times. ∴Ef=4 Ei          ​∴ ΔE=Ef− Ei  =4 Ei-Ei  =3Ei        

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