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Q.

A particle moving with uniform retardation covers distances 18 m. 14 m and 10 m in successive seconds. It comes to rest after travelling a further distance of        

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a

50 m

b

12 m

c

8 m

d

42 m

answer is B.

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Detailed Solution

During uniform retardation in successive seconds 9x,7x,5x,3x,1x

4x=8⇒x=2 in last seconds

s=3x+x=4x

s=4(2)=8m

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