A particle moving with uniform acceleration along x–axis is at $x_1=10\text{\hspace{0.17em}m}$ and $x_2=20\text{\hspace{0.17em}m}$ at t = 6 s and t = 10 s respectively. If its velocity at t = 6s is ${\text{0.5ms}}^{-\text{1}}$, its acceleration is 

${\text{t}}_{\text{1}}=\text{6sec}$                     ${\text{t}}_2=10\sec$                $\text{t}={\text{t}}_{\text{2}}-{\text{t}}_{\text{1}}=10-6$

${\text{u}}_1=\text{0.5m/s}$                                                          $\text{t}=4\sec$

$\text{s}=\text{ut}+\frac{1}{2}{\text{at}}^{\text{2}}$

$10=\left(0.5\right)4+\frac{1}{2}\text{a}{\left(4\right)}^2$

$10=\frac{1}{2}4+\frac{1}{2}\text{a}{\left(4\right)}^2$

$10=2+\frac{1}{2}\text{a4×4}$

$\text{10}=2+\text{8a}$

$\text{a}=1{\text{m/s}}^{\text{2}}$

${\text{x}}_{\text{2}}-{\text{x}}_{\text{1}}=\text{s}$

$\text{s}=20-10$

$\text{s}=1\text{0m}$