A particle moving with uniform acceleration has its final velocity v=150+8x m/s where x is the distance travelled by the body. Then the acceleration is

v=150+8x;v2=150+8xddt(v2)=ddt(150+8x);ddt=4=a⇒a=4m/s2

A particle moving with uniform acceleration has its final velocity v=150+8x m/s where x is the distance travelled by the body. Then the acceleration is

v=150+8x;v2=150+8xddt(v2)=ddt(150+8x);ddt=4=a⇒a=4m/s2

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A particle moving with uniform acceleration has its final velocity $v = \sqrt{150 + 8 x} m / s$ where x is the distance travelled by the body. Then the acceleration is

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$+ 4 m / s^{2}$

$- 4 m / s^{2}$

$+ 8 m / s^{2}$

$- 8 m / s^{2}$

answer is A.

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$\begin{array}{l} v = \sqrt{150 + 8 x}; v^{2} = 150 + 8 x \\ \frac{d}{d t} (v^{2}) = \frac{d}{d t} (150 + 8 x); \frac{d}{d t} = 4 = a \Rightarrow a = 4 m / s^{2} \end{array}$

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A particle moving with uniform acceleration has its final velocity v=150+8x m/s where x is the distance travelled by the body. Then the acceleration is

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A particle moving with uniform acceleration has its final velocity $v = \sqrt{150 + 8 x} m / s$ where x is the distance travelled by the body. Then the acceleration is