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Q.

A particle moving with uniform retardation covers distances 18 m. 14 m and 10 m in successive seconds. It comes to rest after travelling a further distance of

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a

42m

b

50m

c

8m

d

12m

answer is B.

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Detailed Solution

s=ut+12at2⇒18=u(1)+12a(1)2

18+14=u(2)+12a(2)2

u = 20ms–1; a= 4ms–2 ; v = u + at

⇒v = 20 – (4)(3) 

⇒v = 8ms–1

v2 - u2 = 2aS 

⇒0 - 64 = 2(-4)S

S = 8m

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A particle moving with uniform retardation covers distances 18 m. 14 m and 10 m in successive seconds. It comes to rest after travelling a further distance of