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Q.

A particle moving with velocity v having specific charge (q/m) enters a region of magnetic field B having width d=3mv5qB at angle 53° to the boundary of magnetic field. Find the angleθ in the diagram.

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a

none

b

60°

c

90°

d

37°

answer is C.

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Detailed Solution

sinθ=dr=3mV5qB(mVBq)

⇒sinθ=35

⇒θ=37°

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