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Q.

A particle of charge +q and mass m is in a uniform magnetic field B=B0z^.  The initial position of the particle is x=0,y=0,z=0, the magnitude of the momentum of the particle is  p0. The particle is so projected that it crosses the point  [x=p0qB0,y=0,z=0]. What is the time (in sec) after which it reaches this point ? Take mq=12πSI units and  B=0.2T.

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answer is 20.

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Detailed Solution

B

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θ=ωt=qBtm sinθ2=a2R θ2=sin1(aqB2p0) t=2mqBsin1(aqB2p0)=2mqB×π6 =12π×1/5×π6=20sec

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