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Q.

A particle of charge q moves with a-velocity  v=ai^ in a magnetic field  B=bj^+ck^ where a, b and c are constants. The magnitude of the force experienced by the particle is

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a

zero 

b

 qab+c

c

 qab2-c21/2

d

 qab2+c21/2

answer is D.

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Detailed Solution

 F=qv×B

   .=q{ai^×bj^+ck^}

    =q(abi^×j^+aci^×k^)

   =qabk^-acj^

   =qa(bk^-cj^)

magnitude of F=qa(b2+c2)1/2

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