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A particle of charge $- 16 \times 10^{- 18} C$ moving with velocity $10 m s^{- 1}$ along x-axis enters a region where a magnetic field of induction B exists along the y-axis and an electric field of magnitude 10⁴ V/m exists along the negative z-axis. If the charged particle continues moving along the x-axis, the magnitude of B is

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$10^{- 3} Wb / m^{2}$

$10^{3} Wb / m^{2}$

$10^{5} Wb / m^{2}$

$10^{16} Wb / m^{2}$

answer is B.

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Detailed Solution

Since particle is moving undeflected.

So, $qE = qvB \Rightarrow B = E / v = \frac{10^{4}}{10} = 10^{3} Wb / m^{2}$

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