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Q.

A particle of mas s M starting from rest undergoes uniform acceleration. If the speed acquired in time T is V, the power delivered to the particle is :

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a

$\frac{1}{2} \frac{{MV}^{2}}{T^{2}}$

b

$\frac{{MV}^{2}}{T^{2}}$

c

$\frac{1}{2} \frac{{MV}^{2}}{T}$

d

$\frac{{MV}^{2}}{T}$

answer is C.

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Detailed Solution

$P_{av} = \frac{W}{t} = \frac{\frac{1}{2} {MV}^{2} - 0}{T} = \frac{{MV}^{2}}{2 T}$

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