A particle of mass 0.5kg is at rest. A force F starts acting on the particle which varies according to the F-t graph shown in figure. Then kinetic energy of the particle at the end of 3 sec is

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625 J

250J

530 J

67J

answer is B.

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Detailed Solution

If ‘p’ be the momentum at the end of 3 sec, then change in momentum = Area under F - t graph

$∴ p - 0 = 10 \times 2 + \frac{1}{2} \times (3 - 2) \times 10 kg - m / s$

$\Rightarrow p = 25 kg - m / s$

$∴ Kinetic energy = \frac{p^{2}}{2 m} = \frac{(25)^{2}}{2 \times 0.5} J = 625 J$

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