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A particle of mass 1 kg is thrown vertically upwards with speed 100 m/s. After 5 sec it explodes into two parts. One part of mass 400 g comes back with speed 25 m/s, what is the speed of the other part just after explosion? $(g = 10 m / s^{2})$

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600 m/s upward

300 m/s upward

100 m/s down ward

100 m/s upward

answer is B.

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Detailed Solution

Velocity after 5 seconds is $100 - (10 \times 5) = 50 m s^{- 1}$

From conservation of momentum

$(1 \times 50) = (- 0.4 \times 25) + 0.6 V$

$0.6 V = (50 + 10) = 60$

$V = 100 m s^{- 1}$ (upward)

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