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A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up is :

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0.5 J

- 0.5 J

- 1.25 J

1.25 J

answer is D.

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Detailed Solution

Maximum height $= \frac{u^{2}}{2 g} = \frac{(5)^{2}}{2 (10)} = 1 .25 m$
W_gravity = -mgh = -1.25J

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