A particle of mass 10g is kept on the surface of a sphere of mass 100 kg and radius 10cm. Then the gravitational force between them is equal to: (Take G = 6.674×10^-11m³kg^-1s^-2)

We have been given that a particle of mass 10kg is kept on the surface of a sphere as shown

$m_1={10}^{-2}kg,m_2=100kg$, G = 6.674×10^-11m³kg^-1s^-2

$r=10cm={10}^{-2}m$

$F=\frac{G\times m_1{m}_2}{r^2}$

$\Rightarrow \mathrm{F}=\frac{6.674\times {10}^{-11}\times {10}^{-2}\times 100}{{\left({10}^{-2}\right)}^2}$

$\Rightarrow \text{F}=6.674\times {10}^{7 }\text{N}$