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A particle of mass 10kg is moving in a straight line. If its displacement, x with time t is given by $x = (t^{3} - 2 t - 10) m$ , then the force acting on it at the end of 4 seconds is

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300 N

240 N

24 N

1200 N

answer is B.

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Detailed Solution

$m = 10 k g, x = (t^{3} - 2 t - 10) m$

$\Rightarrow \frac{d x}{d t} = v = 3 t^{2} - 2 \Rightarrow \frac{d V}{d t^{2}} = a = 6 t$

At the end of 4 seconds, $a = 6 \times 4 = 24 m / s^{2}$

$F = m a = 10 \times 24 = 240 N$

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