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A particle of mass 200g executes a simple harmonic motion, the restoring force is provided by a spring constant 50N/m. The time period is

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0.21s

0.31s

0.62s

0.41s

answer is D.

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Detailed Solution

$T = 2 π \sqrt{\frac{m}{k}} = 2 π \times \sqrt{\frac{0.2}{50}} = 2 π \frac{1}{\sqrt{250}}$ $= \frac{2 π}{5 \times 3.162} = 0.39 = 0.4 s$

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