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Q.

 A particle of mass 2kg is initially at rest.  A force acts on it whose magnitude changes with time.  The force-time graph is shown below.  The velocity of the particle at t=10 sec is 
 

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a

10  ms−1

b

75  ms−1

c

50  ms−1

d

26  ms−1

answer is C.

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Detailed Solution

Area under the force-time graph is impulse i.e., change in momentum.
⇒∆p=12×2×10+2×10+12×2×10+20+12×4×20
⇒mv−u = 10+20+30+40
⇒2×v = 100
⇒v =50m/s

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