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Q.

A particle of mass 4 gm is moving simple harmonically with a period 8 sec and amplitude 8cm. What is its velocity when the displacement is 8cm

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a

8 cm/sec

b

6 cm/sec

c

4 cm/sec

d

zero

answer is D.

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Detailed Solution

$v = ω \sqrt{A^{2} - y^{2}} = ω \sqrt{8^{2} - 8^{2}} = 0$
(or velocity is zero extreme position)

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