A particle of mass 4g is in a gravitational potential V =(800x2 +150) erg / g. Its frequency of oscillation is

U=mv; F=−dUdx−mw2x=−m(1600x)×10−4

A particle of mass 4g is in a gravitational potential V =(800x2 +150) erg / g. Its frequency of oscillation is

U=mv; F=−dUdx−mw2x=−m(1600x)×10−4

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A particle of mass 4g is in a gravitational potential V =(800x² +150) erg / g. Its frequency of oscillation is

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$\frac{5}{π} Hz$

$\frac{1}{5 π} Hz$

$50 πHz$

$\frac{50}{π} Hz$

answer is B.

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$\begin{array}{l} U = mv; F = - \frac{dU}{dx} \\ - {mw}^{2} x = - m (1600 x) \times 10^{- 4} \end{array}$

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A particle of mass 4g is in a gravitational potential V =(800x2 +150) erg / g. Its frequency of oscillation is

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A particle of mass 4g is in a gravitational potential V =(800x² +150) erg / g. Its frequency of oscillation is