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Q.

A particle of mass m and charge Q is placed in an electric field E which varies with time t as E = E0 sinωt . It will undergo simple harmonic motion of amplitude

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a

QE022

b

QE0 2

c

QE0 

d

QE0 2

answer is B.

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Detailed Solution

E=E0sinωt;F=EQ=E0Qsinωt

a=E0Qmsinωtamax=E0Qm

2=E0QmA=E0Q2

 A is amplitude

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