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Q.

A particle of mass m and charge Q is placed in an electric field E which varies with time t as E = E0 sinωt . It will undergo simple harmonic motion of amplitude

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a

QE02mω2

b

QE0 mω2

c

QE0 mω

d

QE0 mω2

answer is B.

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Detailed Solution

E=E0sin⁡ωt;F=EQ=E0Qsin⁡ωt

⇒a=E0Qmsin⁡ωt⇒amax=E0Qm

Aω2=E0Qm⇒A=E0Qmω2

 ( ∵A is amplitude) 

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