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Q.

A particle of mass ‘m’ carrying a charge ‘q’ enter normally into uniform magnetic induction field ‘B’ . The time taken by the particle to traverse 900 arc is

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a

πm2Bq

b

2πmBq

c

πm4Bq

d

πmBq

answer is C.

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Detailed Solution

Bqv=mrω2                       

3600−T

900−?

t=90 T360   =T4 But T=2πω=2πmBq

                         t=2πm4Bq=πm2Bq

 

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