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Q.

A particle of mass m is allowed to oscillate near the minimum point of a vertical parabolic path having the equation X2=4aY  , then the angular frequency of small oscillations of particle is

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a

ga

b

g2a

c

2ga

d

ga

answer is B.

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Detailed Solution

When the particle is displaced by a small angle 

ma=−mg  sinθ   

a=−gsinθ(or)a=−gtanθ
(as  θ  is small)  

Now X2=4aY  

∴  dydx=X2a⇒a=−gX2a

∴ω=g2a  

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