Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A particle of mass m is attached to a long ideal string. The other end of the string is joined to a vertical cylinder fixed on a frictionless horizontal plane as shown in the figure. When the particle is projected with a speed u in a direction perpendicular to the string the particle continues to move on a spiral path of decreasing radius till it strikes the cylinder. While the particle is moving on the spiral path, how will the tension in the string and speed of the particle change?

Question Image

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

Both will remains constant

b

Tension will increase and speed will remain constant

c

Tension will increase and speed will decrease  

d

Both will increase

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Force of tension always remain perpendicular to instantaneous velocity. So work done by it is always zero and speed remains constant. But a given instant of time T=mv2r

Question Image

r  is decrease with time so T is increases

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring