Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9
Banner 10

Q.

A particle of mass M is moving in a circle of fixed radius ‘R’ in such a way that its centripetal acceleration at time ‘t’ is given by n2Rt2 . Where n is a constant,  the power delivered to the particle by the force acting on it is 

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

MnR2t

b

12Mn2R2t2

c

Mn2R2t

d

MnR2t2

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

   Centripetal Acceleration =   n2Rt2=  Vt2R
      Vt2  =  n2R2t2     Vt   =   nRt---(1) differentiate with respect to time t dVtdt  =   nR---(2)
   Tangential Force on the particle is Ft  =   MdVtdt substitute equation (2) Ft  =   M n R---(3) here Vt is speed of the particle 
    power delivered  =FtVt substitute equations (3) and (1) in above equation   power delivered  ==   MnRnRt   =   Mn2R2t
 

Watch 3-min video & get full concept clarity

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon