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A particle of mass m is moving yz-plane with a uniform velocity v with its trajectory running parallel to +ve y-axis and intersecting z-axis at z=a. The change in its angular momentum about the origin as it bounces elastically from a wall at y=constant is

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$mva i$

$- mva i$

$2mva i$

$-2 mva i$

answer is B.

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Detailed Solution

Initially the particle is having a velocity $\vec{v} = v \hat{j}$ and final velocity is $\vec{v} = - v \hat{j}$

this particle is moving along the line $\vec{r} = y \hat{j} + a \hat{k}$

$Δ \vec{L} = \vec{r} \times m (\vec{v_{f}} - \vec{v_{i}})$

$ΔL = 2 mva \hat{i}$

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