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A particle of mass m is placed at the centre of a uniform spherical shell of mass 3m and radius R. The gravitational potential on the surface of the shell is

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$- \frac{3 Gm}{R}$

$- \frac{4 Gm}{R}$

$- \frac{2 Gm}{R}$

$- \frac{Gm}{R}$

answer is C.

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Detailed Solution

Gravitational potential on the surface of the shell is V = Gravitational potential due to particle ( $V_{1}$ ) + Gravitational potential due to shell itself ( $V_{2}$ )

= $- \frac{Gm}{R} + (- \frac{G 3 m}{R}) = - \frac{4 Gm}{R}$

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