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A particle of mass M is placed at the centre of a uniform spherical shell of equal mass radius ‘a’. Find the gravitational potential at point ‘p’ at a distance $\frac{a}{2}$ from the centre

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$- \frac{3 GM}{a}$

$- \frac{2 GM}{a}$

$- \frac{4 GM}{a}$

$- \frac{5 GM}{a}$

answer is A.

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Detailed Solution

$V_{1} = - \frac{GM}{a / 2} = - \frac{2 GM}{a}$

$V_{2} = - \frac{GM}{a}$

$V_{1} + V_{2} = - \frac{3 GM}{a}$

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