A particle of mass ' $m$ ' is raised from the surface of earth to a height $h = 2 R$ . Find work done by some external agent in this process. Here, $R$ is the radius of earth and $g$ the acceleration due to gravity on earth's surface.

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$\frac{2}{3} m g R$

$- \frac{4}{3} m g R$

$\frac{4}{3} m g R$

$- \frac{2}{3} m g R$

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

No information is given about the change in kinetic energy of the particle. So, assuming change in kinetic energy to be zero.

Work done by external agent $=$ change in potential energy

$= Δ U = \frac{m g h}{1 + \frac{h}{R}}$

Substituting $h = 2 R$ , we get, Work done $= \frac{2}{3} m g R$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE