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A particle of mass m lies at a distance ‘r’ from centre of earth. The force of attraction between the particle and earth as a function of distance is $F (r)$

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$F (r) \propto \frac{1}{r^{2}} f o r r < R$

$F (r) \propto \frac{1}{r^{}} f o r r > R$

$F (r) \propto r f o r r < R$

$F (r) \propto \frac{1}{r^{}} f o r r < R$

answer is C.

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Detailed Solution

$r < R : F = \frac{G m M}{R^{3}} r F \propto r r = R : F = \frac{G m M}{R^{2}} r > R : F = \frac{G m M}{r^{2}}$

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