Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A particle of mass m moves in a straight line. If v is the velocity at a distance x from a fixed point on the line and v2=abx2, where a and b are constant, then

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

the motion continues along the positive x-direction only

b

the particle oscillates with a frequency equal to b2π

c

the motion is simple harmonic

d

the total energy of the particle is ma

answer is B, C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

v2=abx2
differentiating both side w.r.t. time
2vdvdt=2bxdxdt dvdt=A (acceleration) 
A=bx
 Hence motion will be S.H.M. ω2=b, 4π2f2=b, f=b2π
 T.E. =122( Amplitude )2=12mbab=12ma

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring