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Q.

A particle of mass m moving in a straight line with momentum p. Starting at time t=0 s, a force f =kt acts in the same direction on the moving particle during time interval T so that its momentum changes from p to 3p. Here k is a constant. The value of T is

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a

2pk

b

2kp

c

2pk

d

2kp

answer is B.

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Detailed Solution

As F = dp dt or kt dt = dp

Integrating both sides, k∫0Tt dt  = ∫p3pdp 

kT22=[3p-p] = 2p T = 2pk 

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