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Q.

A particle of mass m moving with a velocity (3i^ + 2j^) m/s collides with a stationary body of mass M and finally moves with a velocity-2i^+j^ m/s. If mM=113,then

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a

Both (a) and (b) are correct

b

the velocity of the M is 113(5i^+j^)

c

Both (a) and (b) are wrong

d

the impulse is  ± m(5i^+j^)

answer is D.

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Detailed Solution

  m(3i^+2j^)=m(2i^+j^)+Mv Put M=13m         v=(5i^+j^)13               Jm=PfPi   of   m                   =[(2i^+j^)(3i^+2j^)]m(5i^+j^)       JM=+m(5i^+j^)

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