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A particle of mass m oscillates with simple harmonic motion between points $x_{1} and x_{2},$ the equilibrium position being O. Its potential energy is plotted against position x . It will be as given below in the graph:

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answer is D.

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Detailed Solution

Potential energy of particle performing SHM is given by: PE = $\frac{1}{2} {mω}^{2} x^{2}$ i.e., it varies parabolically such that at mean position it becomes minimum ( may be zero) and maximum at extreme Position.

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