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A particle of mass $m_{1}$ moves with speed v and collides head on with a stationary particle of mass $m_{2}$ . The first particle continue to move in the same direction if $m_{1} {/m}_{2}$ is ( $e =$ coefficient of restitution)

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= e

> e^{2}

< e

> e

answer is B.

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Detailed Solution

v_{1} = \frac{m_{1} - {em}_{2}}{m_{1} + m_{2}}

$v_{1}$ Must be $+ ve$ [given in data]

$\to m_{1} + m_{2} is + ve$

$v = + v$

$\Rightarrow m_{1} - {em}_{2} > 0$

$\Rightarrow \frac{m_{1}}{m_{2}} > e$

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