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Q.

A particle of mass $m_{1}$ makes an elastic, one-dimensional collision with a stationary particle of mass $m_{2}$ . What fraction of the kinetic energy of $m_{1}$ is carried away by $m_{2}$ ?

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a

$\frac{m_{2}}{m_{1}}$

b

$\frac{4 m_{1} m_{2}}{{(m_{1} + m_{2})}^{2}}$

c

$\frac{2 m_{1} m_{2}}{{(m_{1} + m_{2})}^{2}}$

d

$\frac{m_{1}}{m_{2}}$

answer is D.

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Detailed Solution

$V_{1} = u_{1} [\frac{m_{1} - m_{2}}{m_{1} + m_{2}}]$

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