A particle of specific charge α (charge per unit mass) is released at time t = 0 from origin with an initial velocity of v→=v0i^ in a uniform magnetic field B→=−B0k^. Find position of particle at any time t.

Center of the circle will be at (0, v0B0α) and its radius is v0B0α. Angle made with negative x-axis w.r.t center of circle is B0αt

A particle of specific charge α (charge per unit mass) is released at time t = 0 from origin with an initial velocity of v→=v0i^ in a uniform magnetic field B→=−B0k^. Find position of particle at any time t.

Center of the circle will be at (0, v0B0α) and its radius is v0B0α. Angle made with negative x-axis w.r.t center of circle is B0αt

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A particle of specific charge $α$ (charge per unit mass) is released at time t = 0 from origin with an initial velocity of $\vec{v} = v_{0} \hat{i}$ in a uniform magnetic field $\vec{B} = - B_{0} \hat{k} .$ Find position of particle at any time t.

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$\frac{v_{0}}{B_{0} α} [\sin (B_{0} αt) \hat{i} - [1 + \cos (B_{0} αt) \hat{j}]]$

$\frac{v_{0}}{B_{0} α} [\sin (B_{0} αt) \hat{i} + \{1 - \cos (B_{0} αt) \hat{j}\}]$

$\frac{v_{0}}{B_{0} α} [\cos B_{0} αt + \{1 - \sin (B_{0} αt) \hat{j}\}]$

$\frac{v_{0}}{B_{0} α} [\sin αt \hat{i} - {1 + \cos (αt) \hat{j}}]$

answer is B.

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Center of the circle will be at (0, $\frac{v_{0}}{B_{0} α}$ ) and its radius is $\frac{v_{0}}{B_{0} α}$ . Angle made with negative x-axis w.r.t center of circle is $B_{0} αt$

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A particle of specific charge α (charge per unit mass) is released at time t = 0 from origin with an initial velocity of v→=v0i^ in a uniform magnetic field B→=−B0k^. Find position of particle at any time t.

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A particle of specific charge $α$ (charge per unit mass) is released at time t = 0 from origin with an initial velocity of $\vec{v} = v_{0} \hat{i}$ in a uniform magnetic field $\vec{B} = - B_{0} \hat{k} .$ Find position of particle at any time t.