A particle P moves along a straight line away from a fixed point 'O' obeying the relation S=16+48t-t3. The particle P at t = 4 is

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A particle P moves along a straight line away from a fixed point 'O' obeying the relation $S = 16 + 48 t - t^{3} .$ The particle P at t = 4 is

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directed along $OP$

directed along $PO$

at rest at the instant

directed perpendicular

answer is C.

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Detailed Solution

$S = 16 + 48 t - t^{2} t = 4 S = 16 + 48 \times 4 - 16 = 192 directed along OP$

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