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Q.

A particle performing uniform circular motion has angular momentum L wrt centre. If its angular frequency is doubled and its kinetic energy is halved, then the new angular momentum is

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a

L4

b

2L

c

4L

d

L2

answer is A.

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Detailed Solution

K.E1=12L1ω1→(1)

K.E2=12L2ω2→(2)

(2)(1)=K.E/2K.E=12L22ωL2L1ω

L2=14L

L2=L4

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