Q.

A particle performs SHM of amplitude A along a straight line. When it is at a distance 3 A2 from mean position, its kinetic energy gets increased by an amount 122A2 due to an impulsive force. Then its new amplitude becomes

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a

52A

b

2A

c

5A

d

32A

answer is C.

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Detailed Solution

Due to impulse, the total energy of the particle becomes

122A2+122A2=2A2  

Let A' be the new amplitude, 

122A2=2A2A=2A

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