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Q.

A particle performs uniform circular motion with an angular momentum L. If the frequency of particle motion is doubled, its kinetic energy is halved, the new angular momentum becomes

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a

2 L

b

4 L

c

L/4

d

L/2

answer is D.

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Detailed Solution

detailed_solution_thumbnail

 We know that L=mr2ω  K.E. =12mv2=12m(rω)2 =12mr2ω2 According to the given problem mr′2(2ω)=1212mr2ω2 r′2=r2/8 New angular momentum L′=mr′2(2ω) ∴ L′=mr2/82ω=L/4

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